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本文实例讲述了Python实现简单查找最长子串功能。分享给大家供大家参考,具体如下:
十年的威宁网站建设经验,针对设计、前端、开发、售后、文案、推广等六对一服务,响应快,48小时及时工作处理。成都全网营销的优势是能够根据用户设备显示端的尺寸不同,自动调整威宁建站的显示方式,使网站能够适用不同显示终端,在浏览器中调整网站的宽度,无论在任何一种浏览器上浏览网站,都能展现优雅布局与设计,从而大程度地提升浏览体验。创新互联从事“威宁网站设计”,“威宁网站推广”以来,每个客户项目都认真落实执行。题目选自edX公开课 MITx: 6.00.1x Introduction to Computer Science and Programming 课程 Week2 的Problem Set 1的第三题。下面是原题内容。
Assume s is a string of lower case characters.
Write a program that prints the longest substring of s in which the letters occur in alphabetical order. For example, ifs = 'azcbobobegghakl', then your program should print
Longest substring in alphabetical order is: beggh
In the case of ties, print the first substring. For example, if s = 'abcbcd', then your program should printLongest substring in alphabetical order is: abc
For problems such as these, do not include raw_input statements or define the variable s in any way. Our automated testing will provide a value of s for you - so the code you submit in the following box should assume s is already defined. If you are confused by this instruction, please review L4 Problems 10 and 11 before you begin this problem set.
代码如下:
# -*- coding:utf-8 -*- #! python2 #判断一个字符串内的字母是否是按字母表顺序 # 如IsStrIncre('abbcdg') 返回 True # IsStrIncre('abbadg') 返回 False # 如果只有一个字符,也返回False def IsStrIncre(s): for cnt in range(len(s) - 1): if len(s) == 1: return False elif s[cnt] > s[cnt+1]: return False return True s = 'abajsiesnwdw'# example code substr = '' for length in range(1, len(s)+1): firstflag = True # a flag to remember the first string that satisfied the requirements # and ignore the strings satisfied the requirements but appeared after for cnt in range(len(s)-length+1): if IsStrIncre(s[cnt: cnt+length]): if firstflag: substr = s[cnt: cnt+length] firstflag = False print 'Longest substring in alphabetical order is: ' + substr
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