vb.net 真的没法画点吗？

.NET确实没有提供画一个像素点得方法

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你可以试一下用FillEllipse填充一个宽1像素，高2像素的椭圆

原理就是FillEllipse的时候，最左边那一列一般都会多出一个一像素的点；高至少要2，少了就什么都画不出来

asp.net中怎么画一些随机点，用VB.NET的

namespace Linfo

{

public partial class VerifyCode : BasePage

{

public Random rand = new Random();

protected void Page_Load(object sender, EventArgs e)

{

string strListCode = "0123456789abcdefghigklmnopqrstuvwxyz";

int num = 0;

string strNum = num.ToString();

string strListNum = "";

for (int i = 0; i = 3; i++)

{

num = this.rand.Next(1, 36);

strListNum = strListNum + strListCode.Substring(num - 1, 1);

}

this.Session["checkcode"] = strListNum;

base.Response.Cookies.Add(new HttpCookie("CheckCode", SHA1(strListNum)));

this.CreateImage(strListNum);

}

private void CreateImage(string checkCode)

{

int iwidth = checkCode.Length * 8;

Bitmap image = new Bitmap(70, 30);

Graphics g = Graphics.FromImage(image);

g.SmoothingMode = SmoothingMode.HighQuality;

Font f = new Font("Arial ", 14f, FontStyle.Bold);

Brush b = new SolidBrush(Color.Black);

Rectangle rect = new Rectangle(0, 0, 80, 30);

HatchBrush hatchBrush = new HatchBrush(HatchStyle.DarkDownwardDiagonal, Color.LightGray, Color.LightSkyBlue);

g.FillRectangle(hatchBrush, rect);

float CPostion = 1f;

for (int i = 0; i checkCode.Length; i++)

{

this.TransformG(g);

SizeF size = g.MeasureString(checkCode[i].ToString(), f);

g.DrawString(checkCode[i].ToString(), f, b, CPostion, 5f);

CPostion += size.Width - 1f;

g.ResetTransform();

}

MemoryStream ms = new MemoryStream();

image.Save(ms, ImageFormat.Jpeg);

g.Dispose();

image.Dispose();

base.Response.ClearContent();

base.Response.ContentType = "image/Jpeg";

base.Response.BinaryWrite(ms.ToArray());

}

private void TransformG(Graphics g)

{

Matrix myMatrix = new Matrix();

int num1 = this.rand.Next(80, 900);

int num2 = this.rand.Next(80, 800);

float dd1 = num1;

float dd2 = num2;

dd1 /= 10000f;

dd2 /= 10000f;

float f1 = dd1;

float f2 = dd2;

myMatrix.Shear(f1, f2);

g.MultiplyTransform(myMatrix);

}

}

}

怎样在VB.net中画一个点呢？

画点：

在PictureBox的Paint事件里面：

dim myGraphics=e.Graphics

Dim myPointArray As Point() = {New Point(0, 0), New Point(50, 30), New Point(30, 60)}

myGraphics.DrawPolygon(myPen, myPointArray)

画圆：

Dim g As Graphics

g = PictureBox1.CreateGraphics

g.FillEllipse(Brushes.Red, x, y, 10, 10)

VB.NET如何在PICTUREBOX里画一个点，或者说是一个可以规定半径的实心圆？我用的是Visual Basic 2005....

自己用GDI+画的 无论什么什么尺寸的picturebox都行

不过别太小了o(∩_∩)o

代码放在哪里自己决定啊

最好是放在 picturebox的resize时间里

每次picturebox大小改变都重画一次坐标

Dim b As New Bitmap(PictureBox1.Width, PictureBox1.Height)

Dim g As Graphics = Graphics.FromImage(b)

g.Clear(Color.White)

Dim p As New Pen(Color.Black)

p.EndCap = Drawing2D.LineCap.ArrowAnchor

g.DrawLine(p, 30, PictureBox1.Height - 30, 30, 30)

g.DrawLine(p, 30, PictureBox1.Height - 30, PictureBox1.Width - 30, PictureBox1.Height - 30)

Dim i As Integer

Dim bs As New SolidBrush(Color.Green)

Dim po As New Point

po.X = 0

po.Y = PictureBox1.Height - 35

For i = 700 To 1000 Step 50

g.DrawString(i, Me.Font, bs, po.X, po.Y)

g.DrawLine(p, po.X + 28, po.Y + 5, po.X + 30, po.Y + 5)

po.Y -= (PictureBox1.Height - 100) / 6

Next

po.X = 30

po.Y = PictureBox1.Height - 30

For i = 0 To 40 Step 5

g.DrawString(i, Me.Font, bs, po.X, po.Y + 5)

g.DrawLine(p, po.X, po.Y + 2, po.X, po.Y)

po.X += (PictureBox1.Width - 100) / 8

Next

PictureBox1.Image = b

求问VB.NET中（注不是VB6.0)没有画点吗，急！！求高手帮忙

Dim b As New Bitmap(320, 200)'定义图像宽高

Dim clrs As Color=Color.Black

for y as int32=1 to 199

for x as int32=1 to 319

if x=y then

clrs = Color.White'假设是对角线，x=y时使用白色

else

clrs = Color.Black'平时使用黑色

endif

b.SetPixel(x, y, clrs)'画点

next

next

b.Save("test.tif", System.Drawing.Imaging.ImageFormat.Tiff)'保存到图片文件

==================

原创例子，祝进步！！

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